Arocket is divided into three sections. the top section is one-eighth the length of the bottom section. the middle section is one-half the length of the bottom section. the total length of the rocket is 208ft. find the length of the top section.

bottom=128  top=16(128/8)   middle=64(128/2)

128+16+64= 208

b=bottom section

1/8b +8/8b +1/2 b=208

13/8 b=208

multiply both sides by 8/13(opposite of 13/8)

b=128

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet