Mathematics, 17.07.2019 08:30 raveransaw
What’s the point slope equation of the line that is perpendicular to y-8=3(x-10) and passes through (-2,7)?
Answers: 1
![\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope = m\implies -\cfrac{1}{3} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-\cfrac{1}{3}[x-(-2)] \\\\\\ y-7=-\cfrac{1}{3}(x+2)](/tpl/images/0099/5213/80314.png)
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What’s the point slope equation of the line that is perpendicular to y-8=3(x-10) and passes through...
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