What is the factorization of 3x2 – 8x + 5? (3x – 1)(x + 5) (3x + 5)(x – 1) (3x – 1)(x – 5) (3x – 5)(x – 1)

D) (3x -5)(x-1)

Step-by-step explanation:

The given expression is

This is a quadratic expression, where the value of a = 3, b = -8 and c = 5

Here we use "ac" method to factorize.

Multiply the value of a and c.

a.c = 3*5 = 15

Now find the factors of 15 such that when you add the factors, we have to get the value of b, that is b = -8

-3*-5 = 15

when we add them, -3 + (-5) = -8

Therefore, the right factors of 15 is -3 and -5

Now we use these factors and rewrite the given expression

Now we group the terms and factorize

Look at the first two terms, the common factor is 3x

In the last two terms 5 is the common factor. So we take the common factor and factorize, we get

= 3x(x -1) -5(x - 1)

= (x -1)(3x -5)

= (3x -5)(x -1)

The answer is D) (3x -5)(x-1)

i dont get the question

step-by-step explanation: