What is the following quotient? 2- square root 8/ 4+ square root 12

The quotient is 2-√3-2√2+√6/-2

Step-by-step explanation:

To find the quotient of the surd

2-√8/4+√12 we will rationalize the surdic equation and this is done by multiplying the equation through with the conjugate of the denominator 4-√12 to have;

2-√8/4+√12 × 4-√12/4-√12

= (2-√8)(4-√12)/(4+√12)(4-√12)

= 8-2√12-4√8+√96/8-12

= 8-2√(3x4)-4√(2×4)+√(16×6)/-8

= 8-4√3-8√2+4√6/-8

4(2-√3-2√2+√6)/-8

(2-√3-2√2+√6)/-2

The quotient is therefore

2-√3-2√2+√6/-2

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.