Gfind the standard form of the equation of the parabola satisfying the given conditions. focus: left parenthesis negative 5 comma 6 right parenthesis; directrix: y equals 2

The focus is above the directrix 4 units (the difference between y=2 and y=6), so you know the parabola opens upward. The distance from either to the vertex is half that, or 2 units. If you call this distance p, the equation of the parabola with vertex (h, k) can be written as

... y = 1/(4p) × (x-h)² +k

In some parts of the world, this is the form referred to as "standard form." Filling in the numbers p = 2, (h, k) = (-5, 4), this is

... y = (1/8)(x +5)² +4

Elsewhere, "standard form" has this multiplied out.

... y = (1/8)x² + (5/4)x + 57/8

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Multiplying out (x+a)² gives x² +2ax +a².

how is that middle school

step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1