The numbers 2-12 are written on cards and placed in the bag. what is the probability of picking an even number then replacing it and then picking a 7?

We have the cards numbered as 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.

Sample number is, n(S)=11.

We pick a card and want to get even number like 2, 4, 6, 8, 10, and 12.

Probability of picking an even number would be :-

P(even numbers) =

Now we replace the card and want to get a 7 in second attempt.

Probability of picking a 7 would be :-

P(number 7) =

Now Probability of this event = P(even numbers) × P(number 7)

Probability =

So final answer is .

the answer will be

5050 i think

step-by-step explanation: