Each statement describes a transformation of the graph of y = lnx. which statement correctly describes the graph of y = ln(x - 7) + 3?

Hello!

The parent function, y = ln(x), has a vertical and horizontal translation.

y = ln(x - h) + k | In this equation, h is the vertical shift, and k is the horizontal shift.

If ln(x - k), then the graph is translated right k units.

If ln(x + k), then the graph is translated left k units.

If ln(x) + h, then the graph is translated up h units.

If ln(x) - h, then the graph is translated down h units.

Therefore, the graph of y = ln(x - 7) + 3 is translated 3 units up and 7 units to the right, which is choice D.

For plato users

D is the correct answer

Step-by-step explanation:

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}