What is 0.8333 forever in a fraction

There are a couple of different approaches you can use for this. Here's one.

1. Determine how many digits repeat. (There is just one repeating digit.)

2. Call your number x. Multiply x by 10 to the power of the number of digits found in step 1.

3. Subtract the original number, then solve for x.

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If you recognize that 0.333... (repeating) is 1/3, then you know that 0.0333... (repeating) is 1/10×1/3 = 1/30. Add that to 0.8 = 4/5 and you get

... 4/5 + 1/30 = 24/30 + 1/30 = 25/30 = 5/6

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)