Given: circle o with diameter ln and inscribed angle lmn prove: is a right angle.

Method 1.

Look at the picture 1.

We have:

Picture 2.

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Method 2. (Picture 3)

ΔLOM and ΔMON are isosceles triangles. Therefore the two angles opposite the legs are equal.

The sum of the internal angles in each triangle is 180°. Thereofre in ΔLMN we have:

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

1/800 is the right answer