Find the smaller of 2 consecutive integers, x, if the sum of the smaller is 3 times the larger is -5. write an equation and solve

You have defined x to be the smaller of two consecutive integers. Then the larger will be (x+1). The given relation is

... (x) + 3(x+1) = -5 . . . . the smaller plus 3 times the larger is -5

... 4x + 3 = -5 . . . . . . . .simplify

... 4x = -8 . . . . . . . . . . subtract 3

... x = -2 . . . . . . . . . . . divide by the coefficient of x

The smaller of the two integers is -2.

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!