Ebisects df, de=2y, and ef=8y-3. find de, ef, and df

de is congruent to ef definition of bisector

de = ef definition of congruency

2y = 8y - 3 substitution

-6y = -3 subtraction property (subtracted 8y)

y = division property (divided by -6)

***************************************************************************

de = 2y = 2( ) = 1

ef = 8y - 3 = 8( ) - 3 = 4 - 3 = 1

de + ef = df segment addition postulate

1 + 1 = df substitution

2 = df simplify

de=1, ef=1, df=2

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40