Which statement is true regarding the graphed functions? f(0) = 2 and g(–2) = 0 f(0) = 4 and g(–2) = 4 f(2) = 0 and g(–2) = 0 f(–2) = 0 and g(–2) = 0

let's analyze each case to determine the solution

case 1) f(0) = 2 and g(–2) = 0

For x=0> find the value of f(0) in the graph> f(0)=4

For x=-2> find the value of g(-2) in the graph> g(-2)=0

therefore

the statement of the case 1) is false

case 2) f(0) = 4 and g(–2) = 4

For x=0> find the value of f(0) in the graph> f(0)=4

For x=-2> find the value of g(-2) in the graph> g(-2)=0

therefore

the statement of the case 2) is false

case 3) f(2) = 0 and g(–2) = 0

For x=2> find the value of f(2) in the graph> f(2)=0

For x=-2> find the value of g(-2) in the graph> g(-2)=0

therefore

the statement of the case 3) is true

case 4) f(–2) = 0 and g(–2) = 0

For x=-2> find the value of f(-2) in the graph> f(-2) is greater than 12

For x=-2> find the value of g(-2) in the graph> g(-2)=0

therefore

the statement of the case 4) is false

therefore

the answer is

f(2) = 0 and g(–2) = 0> this statement is true

312312

step-by-step explanation:

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5