Answer asap ! 1.a real number between √13 and √14 2.an irrational number between 5 and 7 answer both plz

Part A

= 3.6055512.....

= 3.7416573.....

A real number can be any rational or irrational number which does not have imaginary roots. Hence, the number needs to be a positive value. Any number between and will be positive, so we can take any value between these two numbers. So one of the real numbers an be 3.65528... or

Part B

Irrational number is a number whose decimal representation is non-terminating and non-recurring. So an irrational number between 5 and 7 we need a number on the number line between 5 and 7 (i.e. it is greater than 5 and less than 7). We can pick let's say 6, and make the decimal part non-recurring and non-terminating:

6.540540054000540000.....

We can choose any such number where you see after the decimal point it is clear that it's non-repeating non-terminating, since there are infinite number of irrational  numbers between any 2 numbers

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3