Employees at al's super mart constantly reorganize and reshelve merchandise. in doing so, they calculate floor space needed for displays. the algebraic expression l times w gives the floor space needed in square units for a display that measures length l units and width w units. calculate the floor space needed for a display whose length is 6.5 feet and whose width is 6 feet.

39 square feet.

Step-by-step explanation:

In order to solve this we have to pay close attention to what the proble is telling us, it says that the floor spaced needed is calculated by the multiplication of Length by Width, so if we have length and width we just have to multiply them:

Width*Lebgth=Floor space.

6*6,5=Floor space

Floor space= 39 ft^2

SO we know that for a display that has a length of 6,5 and a width of 6 we will need 39 square feet of floor space.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

his chances of getting a coin of higher value is 4/19

step-by-step explanation: