How many ways are there to choose three donuts from 4 varieties if there must be an odd number of glazed donuts? the number of glazed must be 1 or 3?

1 glazed and 2 others     or     3 glazed and 0 others

           1 x 3 x 3               +                 1 x 1 x 1

                9                     +                       1

                                       10

10

b

step-by-step explanation:

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.