For the school play, adult tickets cost 4 and children tickets cost 2. natalie is working at the ticket counter and just sold 20 worth of tickets. what are all of the possible ticket combinations for 20 worth of tickets?

The possible combinations of adult tickets and children tickets are : (0, 10), (1, 8), (2, 6), (3, 4), (4, 2), (5, 0)

Explanation

Suppose, the number of adult tickets is and the number of children tickets is

Given that, adult tickets cost 4 and children tickets cost 2 and Natalie sold 20 worth of tickets. So the equation will be.....

If x = 0, then

If x = 1 , then

If x = 2 , then

If x = 3 , then

If x = 4 , then

If x = 5 , then

If we take x value greater than 5 , then y will become negative which is not possible.

So, the possible combinations of adult tickets and children tickets are : (0, 10), (1, 8), (2, 6), (3, 4), (4, 2), (5, 0)

b

step-by-step explanation:

this is because the profit is decreasing and turning into debt