How to calculate y=2/3x+5 and putting it in a graph

Your given equation is in "slope-intercept" form. That means the coefficient of x, 2/3, is the slope of the line, and its y-intercept is +5.

Then, just by looking at this equation, you know one point on the graph is (0, 5), the y-intercept.

The slope of 2/3 tells you the graph increases by 2 for each 3 units to the right. That is, another point on the graph will be (0+3, 5+2) = (3, 7).

You can graph these two points and draw a line through them to graph the equation.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length