Vera wants to graph a line that passes through (0, 2) and has a slope of . which points could vera use to graph the line? check all that apply. (–3, 0) (–2, –3) (2, 5) (3, 4) (6, 6)

we have

1) The line passes through

2) The slope is equal to

we know that

If a point lies on the graph of the line, then the point must satisfy the equation of the line

Step 1  

Find the equation of the line

we know that

the equation of the line in point-slope form is equal to

we have

substitute in the equation

we will proceed to verify each of the points to determine the solution of the problem

If a point lies on the graph of the line, then the point must satisfy the equation of the line and the equation will be true for the point

Step 2

Point  

Substitute the value of x and y in the equation of the line

-------> is true

therefore

the point   lies on the line

Step 3

Point    

Substitute the value of x and y in the equation of the line

------> is false  

therefore

the point not lies on the line

Step 4

Point  

Substitute the value of x and y in the equation of the line

------> is false  

therefore

the point not lies on the line

Step 5

Point  

Substitute the value of x and y in the equation of the line  

------> is True

therefore

the point lies on the line

Step 6

Point        

Substitute the value of x and y in the equation of the line  

------> is True

therefore

the point lies on the line

therefore

the answer is

Vera could use the points

the point  

the point

the point

using a graphing tool

see the attached figure to better understand the problem

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation:

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94