In △abc al is an angle bisector (l∈ bc ). point m∈ ab so that lm=am=bm. find the angles in △abc, if ac=2al.

Since LM = AM, point M must be on the perpendicular bisector of AL. Since AM = BM, BL must be perpendicular to AL. This makes ∆ALC a right triangle with hypotenuse AC twice the length of side AL. Hence ∠LAC = ∠LAB = 60°, and AL is angle bisector, median, and altitude.

ΔABC is isosceles with ∠A = 120°, and ∠B = ∠C = 30°.

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step-by-step explanation:

5+2x=a

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