Find the equation of the line which passes through the point (-3,5) and is perpendicular to 3y=6. express your answer in slope-intercept form.

3y = 6 is equivalent to y=2, a horiz. line.  A line perpendicular to y = 2 is a vertical line whose slope is undefined.  The equation of the new line passing thru (-3,5) and perpendicular to y = 2 is x = -3.  This cannot be written in slope-intercept form because the slope is undefined.

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step-by-step explanation:

333.74 ! should be your answer for this question