Solve x + 3y + z = 1 2x – y – z = 6 5x + y + z = 1 (1, 6, 1) (1, 2, -6) (2, 1, -4) (-1, -2, 6)

Answer is (1, 2, -6)

x + 3y + z = 1   > first equation

2x – y – z = 6  > second equation

5x + y + z = 1 > third equation

Add second and third equation

2x – y – z = 6  > second equation

5x + y + z = 1 > third equation

7x = 7 (divide by 7 on both sides)

So x= 1

Now we add first and second equations

x + 3y + z = 1   > first equation

2x – y – z = 6  > second equation

3x +2y = 7

We already got x=1, replace it in the above equation

3(1) + 2y = 7

3 + 2y = 7 (subtract 3)

2y = 4 (divide both sides by 2)

So y =2

Now plug in the values in first equation

x + 3y + z = 1   > first equation

1 + 3(2) + z = 1

7 + z = 1 (subtract 7 from both sides)

z = -6

Answer is (1, 2, -6)

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.