Find the range of the following peicewise function

Range are the y-values. Plug the x-values into the equation and solve for y.

f(x) = 3x - 2

f(-1) = 3(-1) - 2

     =   -3  - 2

     = -5

f(0) = 3(0) - 2

     =   0  - 2

      = -2

R: -5 ≤ y < -2   ⇒   [-5, -2)

f(x) = 2x + 3

f(0) = 2(0) + 3

     =   0  + 3

     =    3

f(5) = 2(5) + 3

      =  10 + 3

      =  13

R: 3 ≤ y < 13    ⇒  [3, 13)

Now, put them together:  [-5, -2) U [3, 13)

A

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step-by-step explanation:

ez do it yourself lazy

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.