What is the factorization of the trinomial below -2x^3-2x^2+12x

-2x^3 - 2x^2 + 12x

Because we can pull out a common factor, we'll do that first to simplify the expression.

-2x(x^2 + x - 6)

Now, let's see if we can split the middle term.

Display factors of -6.

-6 * 1

-1 * 6

-3 * 2

3 * -2 (these digits satisfy the requirements for splitting the middle term)

Split the middle term.

-2x(x^2 + 3x - 2x - 6)

Group terms in pairs of two.

-2x((x^2 + 3x) - (2x - 6))

Factor each binomial.

-2x((x(x + 3)) - (2(x + 3)))

Rearrange the terms.

-2x(x - 2)(x + 3) is the fully factored form of the provided trinomial.  

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

40 i don’t know lololol