The look-out point of a lighthouse is 50 feet above sea level. a woman observes a boat in the water from the look-out point. the angle of depression to the boat in the water is 20°. what is the distance from the base of the light house to the boat in the water?

137.4 feet

Step-by-step explanation:

Consider the attached diagram. The given angle of depression from the lighthouse to the boat is the same as the angle of elevation from the boat to the lighthouse. The trig relationship for tangent tells you ...

... tan(20°) = opposite/adjacent = AL/AB = 50'/AB

Solving for AB, we get

... AB = 50'/tan(20°) ≈ 50'/0.36397

... AB ≈ 137.4'

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn