Find the vertex of this parabola. y = -2x2 + 4x + 12 a. (-4, 12) b. (-2, 6) c. (3, 6) d. (1, 14)

D

given the equation of a parabola in standard form : ax² + bx + c = 0 ( a ≠ 0 )

then the x-coordinate of the vertex  = -

y = - 2x² + 4x + 12 is in standard form

with a = - 2, b= 4 and c = 12

= - = 1

substitute x = 1 into the equation for y

y = - 2(1)² + 4(1) + 12 = 14

vertex = (1, 14 )

the answer is a

step-by-step explanation:

sine

step-by-step explanation: