If x=log3/5,y=log5/7,z=log root7/3,find the value of x+y+z

Given:

x=log(3/5)

y=log(5/7)

z=log(sqrt(7/3)

Find x+y+z

Steps:

Using the law of logarithms, log A + log B = log (AB), we get

x+y+z

=log(3/5)+log(5/7)+log(sqrt(7/3)

=log(3/5*5/7*sqrt(7/3))

=log(3/7*sqrt(7/3)

=log((sqrt(3/7)*sqrt(3/7)*sqrt(7/3))

=log((sqrt(3/7)*sqrt(3/7*7/3))

=log(sqrt(3/7)*1)

=log(sqrt(3/7))

Now apply another law of logarithms,  log(sqrt(A)) = (1/2) log(A)

=(1/2)log(3/7)

which is the final answer.

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.