Gi bisects dgh so that m dgi is x-3 and migh is 2x-13 find the value of x

x = 10

since GI bisects ∠DGH then ∠DGI = ∠IGH, hence

2x - 13 = x - 3 ( subtract x from both sides )

x - 13 = - 3 ( add 13 to both sides )

x = 10

x=10

Step-by-step explanation:

Remember that bisect in math means that something is cut in exactly two halfs, this means that both resultant segments will be equal so we can equalize them into an equation:

DGI=IGH

x-3=2x-13

No we just clear X to solve the equation:

2x-x=-3+13

x=10

So the value of X will be 10

it has the same slope and a different y-intercept

hope this : )

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?