Ineed to find right angle triangle sides (a=? , b=? , c= cathetus-cathetus=1 (a-b=1) and perimeter is 12.

Sides of triangle = 3 , 4 and 5

Explanation:

We have a - b = 1 --------------Equation 1

Perimeter = 12

a + b + c = 12 --------------Equation 2

And we have by Pythagoras theorem, c² = a² +  b² --------------Equation 3

From equation 2 we have c = 12 -a -b, substituting in equation 3

    --------------Equation 4

From equation 1 we have a = 1+b, substituting in equation 4

b = 20 is not possible since perimeter is only 12.

So, b = 3

Substituting in  equation 1 and 2

   a - 3 = 1, a = 4

   3 + 4 + c = 12, c= 5

Sides of triangle = 3 , 4 and 5    

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?