Araindrop drops from a window ledge of a building. the window ledge is 80 feet above the ground. how long does it take before the drop passes by another window ledge that is 16 feet above the ground?

It takes 2 seconds before the drop passes through another window ledge that is 16 ft above the ground.

Step-by-step explanation:

The formula to find time is

Here the drop falls from a window which at a height of 80 ft.

Hence the initial velocity = 0 = u

Now when it passes through a widow at a height of 16 ft, it has covered a distance of = 80-16 = 64 ft = d

It is falling under the gravity so its acceleration = g = 9.8 m/s² = 32 ft /s²

Substituting the values in the formula we get

Dividing both sides by 16 we get

Taking square root on both sides we get

hence, the required result is

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

we have to compute b-a which means subtracting corresponding elements of a from b.

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answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.