If the side of the square is (4x-2y) what is the perimeter of the square

The perimeter of a square is a^2. In this case a= (4x-2y) so a^2=(4x-2y)^2 , a^2={16(x)^2-16xy+4(y)^2}

560

hope this : )

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)