What is the distance between (-15,1) and (-15,6)

So you would use the distance formula which is the square root of (x2-x1)^2 + (y2-y1).

Step-by-step explanation:

So it would be the square root of (-15-(-15)^2 + (6-1)^2

(-15-(15)^2 is the same thing as (-15+15)^2.

(-15+15)^2 is equal to 0^2 which is, 0.

(6-1)^2 is equal to 5^2, which is 25.

So the square root of 0 + 25 is the same thing as radical 25.

Radical 25 is equal to 5.

So, the final answer is 5.

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct