Eight trials are simulated. the results are shown in the table. simulation 105 104 110 112 114 106 108 109 what is the estimated margin of error, using standard deviation? enter your answer, rounded to two decimal places, in the box. ±

2.897

Step-by-step explanation:

Let us find the mean and variance for the sample first.

105104110112

114106108109

Mean = sum/8 = 108.5

Variance = 12

Std dev = sq rt of variance = 3.464

Std error = std dev/ sq rt n

since n =8, we get std error = 1.225

Since sample size is small, df =8-1 =7

For 95% confidence intervals, t critical value for two tailed=2.365

Margin of error = std error x t critical = 1.225(2.365)

=2.897

c

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!