Abag has four green marbles, three red marbles, and three yellow marbles. what is the probability that you pick a red marble, do not replace it, and pick a yellow marble? 2/15 1/15 1/9 1/10

1/10

Step-by-step explanation:

four green marbles, three red marbles, and three yellow marbles

Original total number of marbles: 4 + 3 + 3 = 10

First pick

Picking a red marble. There are 3 red marbles.

p(red) = 3/10

Second pick

Since the red marble picked is not replaced, now the total is 9 marbles.

Picking a yellow marble. There are 3 yellow marbles.

p(yellow) = 3/9 = 1/3

The probability of both events is the product of the individual probabilities.

p(red then yellow) = 3/10 * 1/3 = 1/10

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

step- i d k and i d c : )

you: : 0

bye