Tickets for a school dance were sold over a 3 week period. one third of the tickets were sold on the first week, 56 tickets were sold on the second week, and half of the remaining tickets were sold on the third week. if there are 47 tickets left over, how many tickets were in the beginning of the ticket sale? can u solve and show me how

121

Step-by-step explanation: 1/3 were sold on the first week, tickets had been sold for 3 weeks and 56 was sold on the 2nd week and 47 tickets were left over, so a third of 56 is 18 + 56 =74 +47 total = 121

225

Step-by-step explanation:

Let x be the number of tickets available at the beginning . Then we have the equation:-

x - 1/3x - 56  - 1/2( x - 1/3x - 56) = 47

x - 1/3x - 1/2x + 1/6x  - 56 + 28 = 47

1/3 x = 75

x = 3*75 = 225  answer

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group