Which answer best describes the complex zeros of the polynomial function? f(x)=x3+x2−8x−8 the function has two real zeros and one nonreal zero. the graph of the function intersects the x-axis at exactly one location. the function has one real zero and two nonreal zeros. the graph of the function intersects the x-axis at exactly one location. the function has three real zeros. the graph of the function intersects the x-axis at exactly three locations. the function has one real zero and two nonreal zeros. the graph of the function intersects the x-axis at exactly two locations.

The answer best describes the zeros of the polynomial function f(x)=x^3+x^2−8x−8 is third option:

The function has three real zeros. The graph of the function intersects the x-axis at exactly three locations.

Step-by-step explanation:

Using Ruffini:

f(x)=x^3+x^2-8x-8

   ! 1      1      -8  -8

-1 !___ -1___0__8

     1     0      -8    0

      x^2        -8

f(x)=(x+1)(x^2-8)

Factoring the quadratic term x^2-8, using:

a^2-b^2=(a+b)(a-b)

with:

a^2=x^2→sqrt(a^2)=sqrt(x^2)→a=x

b^2=8→sqrt(b^2)=sqrt(8)→b=sqrt(4*2)→b=sqrt(4) sqrt(2)→b=2 sqrt(2)

x^2-8=(x+2 sqrt(2))(x-2 sqrt(2))

f(x)=(x+1)(x+2 sqrt(2))(x-2 sqrt(2))

Zeros of the polynomial are: x=-1, x=-2 sqrt(2), and x=2 sqrt(2)

The function has three real zeros. The graph of the function intersects the x-axis at exactly three locations.

answer: what

step-by-step explanation:

answer: all the values are within because it has a pattern that repeats from -6 to 4.

good luck!