Which statement is true about the local minimum of the graphed function? over the interval [–4, –2], the local minimum is 0. over the interval [–2, –1], the local minimum is 25. over the interval [–1, 4], the local minimum is 0. over the interval [4, 7], the local minimum is -7.

if your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:

max = c - (b2 / 4a).

the first step is to determine whether your equation gives a maximum or minimum.

-x2 + 4x - 2.     thats an example hope it

step-by-step explanation:

which statement is true about the local minimum of the graphed function?

over the interval [–4, –2], the local minimum is 0.

over the interval [–2, –1], the local minimum is 25.

over the interval [–1, 4], the local minimum is 0.

over the interval [4, 7], the local minimum is -7.

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this