b(1)=−7 b(n)=b(n−1)+12 find the 4th term in the sequence

4th term = 29

to generate the terms, substitute n = 2, 3, 4 into the rule

noting that b(1) = - 7

b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5

b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17

b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29

 The 4th term in the sequence is 29 .

Step-by-step explanation:

The given recursive formula for the sequence :

To find : 4th term

At n=2 , we have

  (Second term)

At n=3 , we have

 (Third term)

At n=4 , we have

 (Fourth term)

Therefore , the 4th term in the sequence is 29 .

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b