Find the slope intercept equation of the line perpendicular to the line 2x-5y=6 and containing the point (2,2)

The equation of the perpendicular line would be y = -5/2x + 7

Step-by-step explanation:

In order to find this line, we must first find the slope of the original line. We do this by solving for y.

2x - 5y = 6

-5y = -2x + 6

y = 2/5x - 6/5

This shows us a slope of 2/5. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negate 2/5 to get -2/5 and then we flip it to get -5/2. Now that we have this, we can use the slope and the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 2 = -5/2(x - 2)

y - 2 = -5/2x + 5

y = -5/2x + 7

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180