If f(x)=1/9x-2, what is f^–1(x)? a.) f^–1(x) = 9x + 18 b.) f^-1(x)=1/9x+2 c.) f^–1(x) = 9x + 2 d.) f^-1(x)=-2x+1/9

f(x)=19x+2→ Switch the f(x) with a y

y=19x+2→ Switch the places of the x and the y variables

x=19y+2→ Solve for y

x−2=19y

y=9x−18

The inverse is f−1(x)=9x−18

Option A is correct

Step-by-step explanation:

Given the function:

Let y = f(x)

then;

Replace x and y values we have;

Add 2 to both sides we have

Multiply both sides by 9, to solve for y

or

y = 9(x+2)

replace then;

⇒

therefore, the inverse of f(x) is,

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: