Write an equation of a line in slope intercept form to the given line and pass through the given pointy = 4x + 6 ; (4,8)i'm not sure as to how to start or what steps to use

Slope intercept form is:

y = mx + b

"m" is the slope, "b" is the y-intercept (when x = 0)

I'm assuming that the equation of a line is parallel to the given line.

When lines are parallel, they have the same slope.

The given line's slope is 4, so the parallel line's slope is also 4

y = mx + b

y = 4x + b

To find b, you plug in the point (4,8) into the equation.

y = 4x + b

8 = 4(4) + b

8 = 16 + b  Subtract 16 on both sides

-8 = b

Your equation is:

y = 4x - 8

answer: there are 453.592 grams in a pound.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3