Asingle die is rolled one time. find the probability of rolling a number greater than 3 or less than 2

The probability of rolling a number greater than 3 or less than 2 is 2/3

If a number greater than 3 is rolled, event putcome will be E = {4, 5, 6}

Pr(greater than 3) = 3/6

If a number less than 2 is rolled, event outcome will be E = {1}

Pr( number greater than 3 or less than 2) = 3/6 + 1/6 = 4/6

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There are 6 numbers on a die : 1, 2, 3 , 4, 5 , 6

numbers greater than 3 are 4, 5 and 6

number less than 2 is 1

There are 4 possible outcomes from 6, hence

Probability = =

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3