Set up an algebraic equation and then solve the following problems. the height of a projectile launched upward at a speed of 32 feet/second from a height of 48 feet is given by the function: h(t)=-16t^2+32t+48. how long will it take the projectile to hit the ground?

3 seconds

solve for when y is zero

0 = -16t^2 + 32t + 48

0 = -16(x^2-2x-3)

0 = -16(x-3)(x+2)

x = 3 or -2

-2 is extraneous because time is not negative in this instance so 3 seconds.

t=-1 +square root of 2 or t=-1 - square root of 2 is the answer i think

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.