91. if there is no real number solution to the quadratic equation, x^2+2x+c=0, what is a possible value of c? 1 -20 3

For no real solution, you must have b^2 - 4ac of the quadratic formula be less than 0.

a = 1; b = 2; c = C

b^2 - 4ac < 0

2^2 - 4(1)(C) < 0

4 - 4C < 0

-4C < -4

C > 1

The only choice greater than 1 is 3.

the 4th choice, 3

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )