What are the values of x in the equation x2 – 6x + 9 = 25? x = –2 or x = 8 x = –1 or x = –11 x = 1 or x = 11 x = 2 or x = –8

The answer is A, x= -2 or x= 8

Step-by-step explanation:

x = –2 or x = 8

Step-by-step explanation:

x²-6x+9 = 25

Subtracting 25 from both the sides,

x²-6x+9-25 = 25 -25

Cancelling out 25 and -25 from the right side

x²-6x+9-25 = 0

1x²-6x-16 = 0

Multiplying the quotient of the first term with the last term,

1*(-16) = -16

We need to find out two such factors of -16 which when added gives us the middle term coefficient -6.

-8 and 2 are such factors of -16, which when added gives us the middle term coefficient -6.

So, we rewrite the middle term -6x as -8x+2x

x²-8x+2x-16 = 0

Factor out x from the first two terms

x(x-8) + 2x-16 = 0

Factor out 2 from the last two terms

x(x-8) + 2(x-8) = 0

Factor out (x-8) from both the terms

(x-8)(x+2) = 0

Either x-8 = 0 or x+2=0

Solving x-8=0, we get x = 8

Solving x+2=0, we get x= -2

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v