Chapman’s brickyard sells bricks and blocks. a brick costs $0.38 and a block costs $1.56. the brickyard filled a $24.80 order, which contained 28 items

number of bricks = 16 and number of blocks  = 12

Step-by-step explanation:

From given information it seems , we need to determine number of bricks and number of blocks.

lets assume number of bricks = x

and number of blocks = y

since total items in brickyard is 28

⇒  number of bricks + number of blocks = 28

⇒ x + y = 28         equation 1

Given that cost of 1 brick = $0.38  and cost of 1 block =$1.56

so cost of x bricks = cost of 1 brick × x = 0.38x

And cost of y blocks = cost of 1 block × y = 1.56y

total cost of 28 items order = $24.80

total cost of 28 items = cost of x bricks + cost of y blocks

⇒0.38x + 1.56y = 24.80 equation 2

Now we are having following two equations

x + y = 28         equation 1

0.38x + 1.56y = 24.80 equation 2

from equation 1 we get x = 28 - y , substituting this value of x in equation 2 we get

0.38(28 - y) + 1.56y =  24.80

⇒10.64-0.38y+1.56y= 24.80

⇒1.18y = 24.80 - 10.64

⇒y = 14.16÷1.18 = 12

substituting value of y in equation 1 we get

x + 12 = 28

⇒x = 16

hence  number of bricks = x  = 16 and number of blocks = y = 12