Triangle ijk is congruent to triangle pqr. if the measure of angle i=3x+4 and the measure of angle p=72-x, then determine the value of x

X = 17°

Step-by-step explanation:

Given that triangle Δ IJK ≅ triangle Δ PQR.

Using CPCTC (corresponding parts of congruent triangles are congruent), we can say angle ∠I = angle ∠P.

given angle ∠I = 3x + 4, and angle ∠P = 72 - x.

Now solving angle ∠I = angle ∠P.

3x + 4 = 72 - x

3x = 72 - x - 4

3x = 68 - x

3x + x = 68

4x = 68

x = 68/4 = 17 degrees.

Hence, the value of x is 17°.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

step-by-step explanation: