Aball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity of 80 feet per second. the distance, s (in feet), of the ball from the ground after t seconds is given by the function: () = 96 + 80 − 16 2 a. how long does it take for the ball to reach its highest point? b. what is the maximum height the ball reaches?

It takes 2.5 seconds for the ball to reach its  highest point

Maximum height is 196 feet

Step-by-step explanation:

h(t) = -16t^2+80t +96

a=-16, b= 80, c=96

To find the maximum height , we need to find vertex

Let find x coordinate of vertex

Plug in the values

It takes 2.5 seconds for the ball to reach its  highest point

Now plug in 2.5 for t to find maximum height

Maximum height is 196 feet

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92