What are the zeros of the polynomial functio ? f(x)=x^3+x^2-9x-9

x = - 1

x1 = - 3

x2 = 3

Step-by-step explanation:

x^2(x + 1) - 9(x + 1)    = f(x)                  x + 1 is a common factor

(x + 1) [ x^2 - 9]          = f(x)                 factor x^2 - 9

(x + 1)(x - 3)(x + 3)

x + 1 = 0

x = - 1

x - 3 = 0

x = 3

x + 3 = 0

x = - 3

Answer

x = - 1

x1 = - 3

x2 = 3

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.