Can u me with another problem . problem: which of these following equations has no solution of y=2? select three apply a: 3(x+4)=16x-14 b: 5x-11=6x-x-11 c: 4x+9=2(2x+9) d: 12+7=-2x-3)+16x e: 1/2x=4

In order to find which Equation does no result in a Solution of X = 2, We need to solve all the Equations one by one and check the result obtained.

✿ Option (A)

Given : 3(X + 4) = 16X - 14

⇒ 3X + 12 = 16X - 14

⇒ 16X - 3X = 14 + 12

⇒ 13X = 26

⇒ X = 2

This Equation has a Solution : X = 2. So, This is not the Equation we are looking for. .

✿ Option (B)

Given : 5X - 11 = 6X - X - 11

⇒ 5X - 11 = 5X - 11

The Equations are Both the Same. So, it has Infinitely Many Solutions which Includes the Solution of X = 2. Hence, This is not the Equation we are looking for.

✿ Option (C)

Given : 4X + 9 = 2(2X + 9)

⇒ 4X + 9 = 4X + 18

⇒ 4X - 4X = 18 - 9

⇒ 0 = 9

This Equation has No Solution.

Hence, This Equation has No Solution of X = 2

✿ Option (D)

Given : 12 + 7 = -(-2X - 3) + 16X

⇒ 19 = 2X + 3 + 16X

⇒ 18X = 19 - 3

⇒ 18X = 16

This Equation has No Solution of X = 2

✿ Option (E)

This Equation has No Solution of X = 2

Hence : The Equations which has No Solution of X = 2 are C - D - E

linear

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!