Our oranges and 5 apples cost 3.56$ three oranges and four apples cost $2.76.find the cost of an orange and the cost of an apple

Two equations for the purchase prices can be written. Let o and a represent the costs of an orange and an apple, respectively.

... 4o +5a = 3.56

... 3o +4a = 2.76

We can eliminate the o variable by subtracting 3 times the first equation from 4 times the second:

... 4(3o +4a) -3(4o +5a) = 4(2.76) -3(3.56)

... a = 0.36 . . . . simplify

This value can be substituted into either equation to find o. Let's use the first one.

... 4o +5·0.36 = 3.56

... 4o = 1.76 . . . . . . . . . subtract 1.80

... o = 0.44 . . . . . . . . . divide by 4

The cost of an orange is $0.44; the cost of an apple is $0.36.

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Comment on the solution

There are perhaps half a dozen different ways to solve a pair of linear equations in two variables. This method isn't necessarily the easiest, but it works. If you have a graphing calculator, quite often it includes matrix operations that will solve this quickly and easily.

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480

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step-by-step explanation: